1.) What are some of the advantages and disadvantages of using a graphing calculator to answer questions about linear situations?
Some advantages of using a graphing calculator for solving questions about linear situations are, with a graphing calculator you just put in the coordinates and you get the answer; so you don’t have to do the math yourself. Some disadvantages of using a graphing calculator for solving questions about linear situations are, when you use a graphing calculator the calculator does all the work for you. The math that it takes to get the answer helps you learn. So, with a calculator, you aren’t doing that math.
2.) Explain how to find the y-intercept of a linear relationship from a table, from a graph, and from an equation.
You can find it on a graph if the line goes over the y axis. You can find it in an equation if the equation has the letter b in it which represents (0,b), which is the y intercept. You can find it in a graph if the graph equals (0,b).
3.) In Investigation 2, you explored the effect that the rate has on the graph of a linear relationship. In this investigation, you looked at the meaning of particular points on the graph, including the y intercept. Summarize what you now about the graph of a linear equation of the form y = mx + b.
The graph of the linear equation y = mx + b is a y intercept. Meaning that the answer is on the y axis. With this equation the answer is (0,3), the 3 is on the y axis and there is nothing on the x axis hence the 0. The y intercept means that the answer is only on the y axis.
4.) To check whether a given point fits a linear relationship, you can make a table, trace a graph, or substitute the coordinates into an equation, you need to be careful about the order in which you do the calculations. Check whether the point (-2, 13) is on the line y = 5 – 4x by substituting the coordinates into the equation. Show and explain each step you take so that it is easy to see the order in which you did your calculations.
Mathematical Reflections 3 p.52 Hah
May,28,2009
1.) What are some of the advantages and disadvantages of using a graphing calculator to answer questions about linear situations?
Some advantages of using a graphing calculator for solving questions about linear situations are, with a graphing calculator you just put in the coordinates and you get the answer; so you don’t have to do the math yourself. Some disadvantages of using a graphing calculator for solving questions about linear situations are, when you use a graphing calculator the calculator does all the work for you. The math that it takes to get the answer helps you learn. So, with a calculator, you aren’t doing that math.
2.) Explain how to find the y-intercept of a linear relationship from a table, from a graph, and from an equation.
You can find it on a graph if the line goes over the y axis. You can find it in an equation if the equation has the letter b in it which represents (0,b), which is the y intercept. You can find it in a graph if the graph equals (0,b).
3.) In Investigation 2, you explored the effect that the rate has on the graph of a linear relationship. In this investigation, you looked at the meaning of particular points on the graph, including the y intercept. Summarize what you now about the graph of a linear equation of the form y = mx + b.
The graph of the linear equation y = mx + b is a y intercept. Meaning that the answer is on the y axis. With this equation the answer is (0,3), the 3 is on the y axis and there is nothing on the x axis hence the 0. The y intercept means that the answer is only on the y axis.
4.) To check whether a given point fits a linear relationship, you can make a table, trace a graph, or substitute the coordinates into an equation, you need to be careful about the order in which you do the calculations. Check whether the point (-2, 13) is on the line y = 5 – 4x by substituting the coordinates into the equation. Show and explain each step you take so that it is easy to see the order in which you did your calculations.
You can check your work by using equations.
y= 5 – 4x (-2,13)
y= 5 -4 -2
y= 5 - -8
y = 13